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线性表练习扑克牌游戏(炸金花)
后端
2024-02-09 09:59:20
炸金花简介
扑克牌游戏炸金花,也叫牌九,是一种常见的博弈游戏。玩家们使用扑克牌来进行游戏,目标是通过比较牌型来赢得筹码。炸金花的玩法非常简单,适合不同年龄段的人群。
游戏规则
- 发牌:玩家们围坐在牌桌旁,发牌者将一副扑克牌洗牌后,逆时针发给每位玩家三张牌,牌面朝下。
- 下注:发牌后,玩家们可以根据自己的牌型进行下注。下注的筹码数额由玩家自己决定。
- 开牌:下注结束后,玩家们可以开牌了。玩家们依次亮出自己的牌型,牌型较大的玩家赢得本轮游戏的筹码。
- 结束:游戏持续进行,直到有一位玩家赢得所有筹码,或者玩家们达成平局。
线性表模拟
扑克牌游戏炸金花可以用线性表来模拟。我们可以将扑克牌看成是一个一维数组,数组中的每个元素都是一张牌。洗牌的过程就是将数组中的元素随机打乱。发牌的过程就是将数组中的元素依次取出,发给每位玩家。游戏的过程就是比较玩家们的牌型,牌型较大的玩家赢得本轮游戏的筹码。
import random
# 构造扑克牌
cards = []
for suit in ['♠', '♥', '♦', '♣']:
for rank in ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']:
cards.append(suit + rank)
# 洗牌
random.shuffle(cards)
# 发牌
players = [[] for _ in range(4)]
for i in range(3):
for player in players:
player.append(cards.pop())
# 游戏过程
while True:
# 下注
bets = []
for player in players:
bet = int(input(f"Player {player + 1}, please enter your bet: "))
bets.append(bet)
# 开牌
for player in players:
print(f"Player {player + 1} shows:")
for card in player:
print(card, end=" ")
print()
# 比较牌型
winner = -1
max_rank = -1
for player in range(len(players)):
rank = evaluate_hand(players[player])
if rank > max_rank:
max_rank = rank
winner = player
# 结算筹码
for player in range(len(players)):
if player == winner:
for bet in bets:
players[player] += bet
else:
players[player] -= bet
# 检查是否结束
if len(players) == 1:
print(f"Player {winner + 1} wins!")
break
# 定义牌型评估函数
def evaluate_hand(hand):
# 同花顺
if is_straight_flush(hand):
return 8
# 四条
if is_four_of_a_kind(hand):
return 7
# 满堂红
if is_full_house(hand):
return 6
# 同花
if is_flush(hand):
return 5
# 顺子
if is_straight(hand):
return 4
# 三条
if is_three_of_a_kind(hand):
return 3
# 两对
if is_two_pair(hand):
return 2
# 一对
if is_one_pair(hand):
return 1
# 散牌
return 0
# 定义同花顺判断函数
def is_straight_flush(hand):
return is_straight(hand) and is_flush(hand)
# 定义四条判断函数
def is_four_of_a_kind(hand):
ranks = [card[1] for card in hand]
return ranks.count(ranks[0]) == 4
# 定义满堂红判断函数
def is_full_house(hand):
ranks = [card[1] for card in hand]
return ranks.count(ranks[0]) == 3 and ranks.count(ranks[1]) == 2
# 定义同花判断函数
def is_flush(hand):
suits = [card[0] for card in hand]
return len(set(suits)) == 1
# 定义顺子判断函数
def is_straight(hand):
ranks = [card[1] for card in hand]
ranks.sort()
for i in range(1, len(ranks)):
if ranks[i] - ranks[i - 1] != 1:
return False
return True
# 定义三条判断函数
def is_three_of_a_kind(hand):
ranks = [card[1] for card in hand]
return ranks.count(ranks[0]) == 3 or ranks.count(ranks[1]) == 3 or ranks.count(ranks[2]) == 3
# 定义两对判断函数
def is_two_pair(hand):
ranks = [card[1] for card in hand]
return ranks.count(ranks[0]) == 2 and ranks.count(ranks[1]) == 2
# 定义一对判断函数
def is_one_pair(hand):
ranks = [card[1] for card in hand]
return ranks.count(ranks[0]) == 2 or ranks.count(ranks[1]) == 2 or ranks.count(ranks[2]) == 2