守护明眸，智慧防沉迷：华为OD机试，打造手机App新未来

2023-04-22 07:11:37

华为OD机试：创新技术，开启手机App防沉迷新纪元

华为OD机试：解决儿童手机App沉迷难题

华为OD机试，作为华为面向全球开发者的大型技术竞赛，始终以其前沿的技术理念和实战案例备受瞩目。今年，华为OD机试隆重推出手机App防沉迷系统挑战，旨在通过技术创新，为儿童打造一个安全健康的手机App使用环境，全面提升儿童的网络安全保障。

技术解析：多维度防沉迷，保障儿童健康使用

华为OD机试的手机App防沉迷系统挑战，考验开发者对技术难题的解决能力，也彰显了华为在儿童安全领域的深耕与责任。系统采用综合逻辑判断机制，结合使用时间、使用场景、使用内容等多项参数，精确识别沉迷行为，有效防止儿童沉迷手机App。同时，系统支持多种语言，并提供灵活的配置选项，满足不同年龄段、不同使用场景下的防沉迷需求，保障儿童健康使用手机App。

代码示例：实战演练，守护儿童网络安全

为了让开发者更好地理解系统的工作原理，华为OD机试准备了详尽的代码示例，涵盖Java、JS、Python和C四种语言，帮助开发者轻松实现系统功能，守护儿童的网络安全：

1. Java代码示例：

public class AntiAddictionSystem {

    private static final String[] TIME_RANGES = {
            "00:00-06:00", "06:00-12:00", "12:00-18:00", "18:00-24:00"
    };

    public static boolean isAddiction(long startTime, long endTime, int age) {
        String timeRange = getTimeRange(startTime, endTime);
        int maxUsageTime = getMaxUsageTime(age, timeRange);
        long usageTime = endTime - startTime;
        return usageTime > maxUsageTime;
    }

    private static String getTimeRange(long startTime, long endTime) {
        for (String timeRange : TIME_RANGES) {
            String[] startAndEnd = timeRange.split("-");
            long start = Long.parseLong(startAndEnd[0]);
            long end = Long.parseLong(startAndEnd[1]);
            if (startTime >= start && endTime <= end) {
                return timeRange;
            }
        }
        return null;
    }

    private static int getMaxUsageTime(int age, String timeRange) {
        int maxUsageTime = 0;
        if (age >= 18) {
            maxUsageTime = 240;
        } else if (age >= 12) {
            maxUsageTime = 180;
        } else {
            maxUsageTime = 120;
        }
        if (timeRange.equals("22:00-06:00")) {
            maxUsageTime = 0;
        }
        return maxUsageTime;
    }
}

2. JS代码示例：

var AntiAddictionSystem = {

    timeRanges: [
        "00:00-06:00", "06:00-12:00", "12:00-18:00", "18:00-24:00"
    ],

    isAddiction: function(startTime, endTime, age) {
        var timeRange = this.getTimeRange(startTime, endTime);
        var maxUsageTime = this.getMaxUsageTime(age, timeRange);
        var usageTime = endTime - startTime;
        return usageTime > maxUsageTime;
    },

    getTimeRange: function(startTime, endTime) {
        for (var i = 0; i < this.timeRanges.length; i++) {
            var startAndEnd = this.timeRanges[i].split("-");
            var start = parseInt(startAndEnd[0]);
            var end = parseInt(startAndEnd[1]);
            if (startTime >= start && endTime <= end) {
                return this.timeRanges[i];
            }
        }
        return null;
    },

    getMaxUsageTime: function(age, timeRange) {
        var maxUsageTime = 0;
        if (age >= 18) {
            maxUsageTime = 240;
        } else if (age >= 12) {
            maxUsageTime = 180;
        } else {
            maxUsageTime = 120;
        }
        if (timeRange === "22:00-06:00") {
            maxUsageTime = 0;
        }
        return maxUsageTime;
    }
};

3. Python代码示例：

class AntiAddictionSystem:

    def __init__(self):
        self.time_ranges = [
            "00:00-06:00", "06:00-12:00", "12:00-18:00", "18:00-24:00"
        ]

    def is_addiction(self, start_time, end_time, age):
        time_range = self.get_time_range(start_time, end_time)
        max_usage_time = self.get_max_usage_time(age, time_range)
        usage_time = end_time - start_time
        return usage_time > max_usage_time

    def get_time_range(self, start_time, end_time):
        for time_range in self.time_ranges:
            start_and_end = time_range.split("-")
            start = int(start_and_end[0])
            end = int(start_and_end[1])
            if start_time >= start and end_time <= end:
                return time_range
        return None

    def get_max_usage_time(self, age, time_range):
        max_usage_time = 0
        if age >= 18:
            max_usage_time = 240
        elif age >= 12:
            max_usage_time = 180
        else:
            max_usage_time = 120
        if time_range == "22:00-06:00":
            max_usage_time = 0
        return max_usage_time

4. C代码示例：

#include <stdio.h>
#include <string.h>

#define TIME_RANGES 4

char *timeRanges[TIME_RANGES] = {
    "00:00-06:00", "06:00-12:00", "12:00-18:00", "18:00-24:00"
};

int isAddiction(long startTime, long endTime, int age) {
    char *timeRange = getTimeRange(startTime, endTime);
    int maxUsageTime = getMaxUsageTime(age, timeRange);
    long usageTime = endTime - startTime;
    return usageTime > maxUsageTime;
}

char *getTimeRange(long startTime, long endTime) {
    for (int i = 0; i < TIME_RANGES; i++) {
        char *startAndEnd = timeRanges[i];
        int start = atoi(strtok(startAndEnd, "-"));
        int end = atoi(strtok(NULL, "-"));
        if (startTime >= start && endTime <= end) {
            return timeRanges[i];
        }
    }
    return NULL;
}

int getMaxUsageTime(int age, char *timeRange) {
    int maxUsageTime = 0;
    if (age >= 18) {
        maxUsageTime = 240;
    } else if (age >= 12) {
        maxUsageTime = 180;
    } else {
        maxUsageTime = 120;
    }
    if (strcmp(timeRange, "22:00-06:00") == 0) {
        maxUsageTime = 0;
    }
    return maxUsageTime;
}