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反转字符串的元音字符:算法之美
闲谈
2024-01-13 04:52:09
题意分析
给定一个字符串s
,你的任务是仅反转字符串中的所有元音字母,并返回结果字符串。元音字母包括'a'、'e'、'i'、'o'、'u'
,且可能以大小写两种形式出现。
解题思路
方法一:双指针
双指针法是一种经典的字符串处理算法,它使用两个指针分别指向字符串的两端,然后从两端向中间移动,比较字符是否相等。如果相等,则交换两个字符,否则继续移动指针。
def reverse_vowels(s):
"""
Reverses the vowels in a string.
Args:
s: The string to reverse the vowels in.
Returns:
The string with the vowels reversed.
"""
# Initialize the left and right pointers.
left, right = 0, len(s) - 1
# Create a set of vowels.
vowels = set("aeiouAEIOU")
# While the left pointer is less than or equal to the right pointer, continue.
while left <= right:
# If the character at the left pointer is a vowel, and the character at the right pointer is a vowel, swap the characters.
if s[left] in vowels and s[right] in vowels:
s = s[:left] + s[right] + s[left+1:right] + s[left] + s[right+1:]
# Move the left and right pointers inward.
left += 1
right -= 1
# If the character at the left pointer is not a vowel, move the left pointer inward.
elif s[left] not in vowels:
left += 1
# If the character at the right pointer is not a vowel, move the right pointer inward.
elif s[right] not in vowels:
right -= 1
# Return the reversed string.
return s
方法二:使用正则表达式
正则表达式是一种强大的工具,它可以用来查找和替换字符串中的文本。我们可以使用正则表达式来查找字符串中的所有元音字母,然后用其对应的相反元音字母替换它们。
import re
def reverse_vowels(s):
"""
Reverses the vowels in a string.
Args:
s: The string to reverse the vowels in.
Returns:
The string with the vowels reversed.
"""
# Create a regular expression that matches all vowels.
vowel_regex = re.compile("[aeiouAEIOU]")
# Find all the vowels in the string.
vowels = vowel_regex.findall(s)
# Reverse the list of vowels.
vowels.reverse()
# Replace the vowels in the string with the reversed list of vowels.
reversed_s = vowel_regex.sub(lambda m: vowels.pop(0), s)
# Return the reversed string.
return reversed_s
性能分析
在性能方面,双指针法和正则表达式法都有各自的优缺点。双指针法的时间复杂度为O(n),其中n是字符串的长度。正则表达式法的