乘最多水的容器: LeetCode 11 的Python题解

2024-02-04 00:49:34

在本文中，我们将逐步解决LeetCode 11题“乘最多水的容器”。我们会从数学角度进行分析，并提供Python代码示例，以帮助您更好地理解解决方案。

题目分析：

题目要求我们找到能够容纳最多水的容器，即两根柱子和坐标轴组成的长方形面积最大。
对于任何两根柱子，它们能够容纳的水的体积取决于它们之间的距离和较短柱子的高度。
我们需要找到两根柱子，使得它们之间的距离和较短柱子的高度之积最大。

Python代码示例：

def maxArea(height):
  """
  Calculates the maximum area of water that can be held by a container formed by two bars.

  Args:
    height: A list of integers representing the heights of the bars.

  Returns:
    The maximum area of water that can be held by a container formed by two bars.
  """

  # Initialize the maximum area and the left and right pointers.
  max_area = 0
  left = 0
  right = len(height) - 1

  # While the left and right pointers have not crossed each other, continue the loop.
  while left < right:
    # Calculate the current area.
    area = (right - left) * min(height[left], height[right])

    # Update the maximum area if the current area is larger.
    max_area = max(max_area, area)

    # Move the left or right pointer to the bar with the smaller height.
    if height[left] < height[right]:
      left += 1
    else:
      right -= 1

  # Return the maximum area.
  return max_area

# Test the function with a sample input.
height = [1, 8, 6, 2, 5, 4, 8, 3, 7]
print(maxArea(height))